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Every measurement in physics has two parts: a numerical value and a unit. Saying "the mass is 5" means nothing without stating "5 kg." The international system of units — called SI (from the French Système International d'Unités) — provides a universal set of base units so that scientists everywhere can communicate results unambiguously. At GCSE level you must be confident converting between units and using standard prefixes.
The SI system is built on seven base quantities. Every other unit in physics (called a derived unit) can be expressed as a combination of these base units.
| Base Quantity | SI Base Unit | Symbol |
|---|---|---|
| Length | metre | m |
| Mass | kilogram | kg |
| Time | second | s |
| Electric current | ampere | A |
| Temperature | kelvin | K |
| Amount of substance | mole | mol |
| Luminous intensity | candela | cd |
For GCSE Combined Science you mainly need the first five. Notice that the kilogram — not the gram — is the base unit for mass. This often catches students out in calculations.
Derived units are combinations of base units. You should recognise the most common ones and be able to break them down.
| Quantity | Derived Unit | Symbol | In Base Units |
|---|---|---|---|
| Force | newton | N | kg m/s² |
| Energy | joule | J | kg m²/s² |
| Power | watt | W | kg m²/s³ |
| Pressure | pascal | Pa | kg/(m s²) |
| Frequency | hertz | Hz | 1/s |
| Charge | coulomb | C | A s |
| Potential difference | volt | V | kg m²/(A s³) |
| Resistance | ohm | Ω | kg m²/(A² s³) |
| Speed | (no special name) | m/s | m/s |
| Acceleration | (no special name) | m/s² | m/s² |
Question: Show that the units of energy (J) are consistent with the equation E = ½mv².
Solution:
A joule is defined as kg m²/s², so the units are consistent. This technique — called dimensional analysis — is a powerful way to check your answers.
Prefixes scale the base unit up or down by powers of ten. You must be able to convert fluently.
| Prefix | Symbol | Multiplier | Power of 10 |
|---|---|---|---|
| tera | T | 1 000 000 000 000 | 10¹² |
| giga | G | 1 000 000 000 | 10⁹ |
| mega | M | 1 000 000 | 10⁶ |
| kilo | k | 1 000 | 10³ |
| (none) | — | 1 | 10⁰ |
| centi | c | 0.01 | 10⁻² |
| milli | m | 0.001 | 10⁻³ |
| micro | μ | 0.000 001 | 10⁻⁶ |
| nano | n | 0.000 000 001 | 10⁻⁹ |
flowchart LR
A["nano (n)\n10⁻⁹"] -->|"×1000"| B["micro (μ)\n10⁻⁶"]
B -->|"×1000"| C["milli (m)\n10⁻³"]
C -->|"×1000"| D["(base unit)\n10⁰"]
D -->|"×1000"| E["kilo (k)\n10³"]
E -->|"×1000"| F["mega (M)\n10⁶"]
F -->|"×1000"| G["giga (G)\n10⁹"]
To convert from a prefixed unit to the base unit, multiply by the prefix value.
To convert from a base unit to a prefixed unit, divide by the prefix value.
Question: A wire is 2.4 km long and has a cross-sectional area of 0.50 mm². Convert both to SI base units.
Solution:
Length: 2.4 km = 2.4 × 10³ m = 2400 m
Area: 0.50 mm² — be careful here. 1 mm = 10⁻³ m, so 1 mm² = (10⁻³)² = 10⁻⁶ m²
0.50 mm² = 0.50 × 10⁻⁶ m² = 5.0 × 10⁻⁷ m²
Question: A household uses 12 kWh of energy per day. Convert this to joules.
Solution:
1 kWh = 1000 W × 3600 s = 3 600 000 J = 3.6 × 10⁶ J
12 kWh = 12 × 3.6 × 10⁶ J = 4.32 × 10⁷ J = 43 200 000 J
Very large and very small numbers are written in standard form: a × 10ⁿ where 1 ≤ a < 10.
| Value | Standard Form |
|---|---|
| 300 000 000 m/s (speed of light) | 3.0 × 10⁸ m/s |
| 0.000 000 001 6 m (radius of atom) | 1.6 × 10⁻⁹ m |
| 6 400 000 m (radius of Earth) | 6.4 × 10⁶ m |
| 0.000 25 A | 2.5 × 10⁻⁴ A |
When multiplying: multiply the numbers and add the powers.
(3.0 × 10⁸) × (2.0 × 10⁻³) = 6.0 × 10⁵
When dividing: divide the numbers and subtract the powers.
(8.0 × 10⁶) ÷ (4.0 × 10²) = 2.0 × 10⁴
Question: The equation for pressure is P = F/A. Verify that the units of pressure (Pa) are consistent.
Solution:
Force F is in N = kg m/s². Area A is in m².
P = F/A has units: (kg m/s²) / m² = kg/(m s²) = kg m⁻¹ s⁻²
This matches the definition of a pascal (Pa). If your final answer does not have the correct units, there is an error in your working.
Question: A signal has a frequency of 2.4 GHz. Express this in (a) Hz, (b) MHz.
Solution:
(a) 2.4 GHz = 2.4 × 10⁹ Hz = 2 400 000 000 Hz
(b) 2.4 GHz = 2.4 × 10⁹ Hz ÷ 10⁶ = 2400 MHz
At GCSE you are expected to give answers to an appropriate number of significant figures (s.f.) — usually the same as the least precise value given in the question.
| Given Values | Appropriate s.f. for Answer |
|---|---|
| 3.5 m, 2.1 s | 2 s.f. |
| 12.0 kg, 9.8 N/kg | 2 or 3 s.f. |
| 250 m, 60 s | 2 s.f. |
| Mistake | Why It Happens | How to Avoid It |
|---|---|---|
| Using grams instead of kg in F = ma | Forgetting kg is the base unit | Always convert mass to kg first |
| Converting mm² or cm³ incorrectly | Squaring/cubing the conversion only once | Square or cube the linear conversion factor |
| Writing 3.5 × 10³ as 3500 then making arithmetic errors | Not staying in standard form | Keep numbers in standard form during calculations |
| Confusing M (mega, 10⁶) with m (milli, 10⁻³) | Both use the letter M | Capital M = mega; lowercase m = milli |
| Giving kWh when asked for joules | Not reading the question carefully | Check what unit the question demands |
| Rounding too early in multi-step calculations | Losing precision at intermediate steps | Keep full calculator display until the final answer, then round |
| Forgetting units in the final answer | Rushing | Always write the unit after your numerical answer |