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Ionic bonding is the transfer of electrons from a metal atom to a non-metal atom, forming charged particles called ions. These oppositely charged ions are held together by strong electrostatic forces of attraction. Understanding ionic bonding requires you to know electron configurations, draw dot-and-cross diagrams, and explain why atoms form ions.
Atoms are most stable when they have a full outer shell of electrons (like a noble gas). Metals have a few electrons in their outer shell and find it easier to lose them. Non-metals are close to a full outer shell and find it easier to gain electrons.
| Atom Type | Outer Shell Electrons | Action | Ion Formed | Charge |
|---|---|---|---|---|
| Metal (Group 1) | 1 | Loses 1 electron | Positive ion (+1) | e.g. Na⁺ |
| Metal (Group 2) | 2 | Loses 2 electrons | Positive ion (+2) | e.g. Mg²⁺ |
| Non-metal (Group 6) | 6 | Gains 2 electrons | Negative ion (−2) | e.g. O²⁻ |
| Non-metal (Group 7) | 7 | Gains 1 electron | Negative ion (−1) | e.g. Cl⁻ |
Metal atoms lose electrons → positive ions (cations)
Non-metal atoms gain electrons → negative ions (anions)
flowchart LR
M["Metal atom\n(e.g. Na: 2,8,1)"] -->|"Loses outer\nelectron(s)"| MI["Metal ion\n(e.g. Na⁺: 2,8)"]
NM["Non-metal atom\n(e.g. Cl: 2,8,7)"] -->|"Gains\nelectron(s)"| NMI["Non-metal ion\n(e.g. Cl⁻: 2,8,8)"]
MI -->|"Electrostatic\nattraction"| BOND["Ionic bond"]
NMI -->|"Electrostatic\nattraction"| BOND
| Atom | Electron Config | Ion | Ion Electron Config | Same Config As |
|---|---|---|---|---|
| Na (11) | 2,8,1 | Na⁺ | 2,8 | Neon |
| Mg (12) | 2,8,2 | Mg²⁺ | 2,8 | Neon |
| Al (13) | 2,8,3 | Al³⁺ | 2,8 | Neon |
| O (8) | 2,6 | O²⁻ | 2,8 | Neon |
| Cl (17) | 2,8,7 | Cl⁻ | 2,8,8 | Argon |
| K (19) | 2,8,8,1 | K⁺ | 2,8,8 | Argon |
| Ca (20) | 2,8,8,2 | Ca²⁺ | 2,8,8 | Argon |
The ions have the same electron configuration as the nearest noble gas — this is why they are stable.
In a dot-and-cross diagram:
Step 1: Na has 1 outer electron (dot). Cl has 7 outer electrons (crosses).
Step 2: Na transfers its 1 electron to Cl.
Step 3: Na becomes Na⁺ (2,8). Cl becomes Cl⁻ (2,8,8).
Step 4: Draw both ions in square brackets with charges.
The electron that was transferred is shown as a dot in the chloride ion's outer shell to show where it came from.
Step 1: Mg has 2 outer electrons. O has 6 outer electrons.
Step 2: Mg transfers both electrons to O.
Step 3: Mg becomes Mg²⁺ (2,8). O becomes O²⁻ (2,8).
One Mg provides exactly the 2 electrons that one O needs, so the ratio is 1:1.
Step 1: Mg has 2 electrons to lose. Each Cl needs 1 electron.
Step 2: Mg transfers 1 electron to each of 2 Cl atoms.
Step 3: Mg becomes Mg²⁺. Each Cl becomes Cl⁻.
The ratio is 1 Mg : 2 Cl, giving the formula MgCl₂.
Ca (2,8,8,2) loses 2 electrons → Ca²⁺
Each F (2,7) gains 1 electron → F⁻
Ratio: 1 Ca : 2 F → CaF₂
The total positive charge must equal the total negative charge (the compound is neutral overall).
| Metal Ion | Non-metal Ion | Formula | Reasoning |
|---|---|---|---|
| Na⁺ | Cl⁻ | NaCl | +1 and −1 balance |
| Mg²⁺ | Cl⁻ | MgCl₂ | +2 needs 2 × (−1) |
| Na⁺ | O²⁻ | Na₂O | 2 × (+1) balances −2 |
| Ca²⁺ | O²⁻ | CaO | +2 and −2 balance |
| Al³⁺ | O²⁻ | Al₂O₃ | 2×(+3) = 3×(−2) = 6 |
| Mg²⁺ | O²⁻ | MgO | +2 and −2 balance |
Quick method: Cross the charges to get the subscripts. For Al³⁺ and O²⁻: Al₂O₃ (the 3 from Al goes to O; the 2 from O goes to Al).
An ionic bond is the strong electrostatic force of attraction between oppositely charged ions.
This definition must be precise in the exam. Key points:
The transfer of electrons creates the ions; the attraction between the ions IS the bond.
Question: Write the ionic equation for the formation of sodium chloride from its atoms.
Solution:
Na → Na⁺ + e⁻ (sodium loses one electron)
Cl + e⁻ → Cl⁻ (chlorine gains one electron)
Overall: Na + Cl → Na⁺ + Cl⁻ → NaCl
Question: Lithium (Group 1) reacts with nitrogen (Group 5). Predict the formula of the compound.
Solution:
Li is in Group 1 → loses 1 electron → Li⁺
N is in Group 5 → has 5 outer electrons → needs 3 more → gains 3 electrons → N³⁻
To balance charges: 3 × Li⁺ (total +3) balances 1 × N³⁻ (total −3)
Formula: Li₃N (lithium nitride)
flowchart LR
G1["Group 1 metals\nLose 1 e⁻\nForm +1 ions"] --> IONIC["Ionic\nCompounds"]
G2["Group 2 metals\nLose 2 e⁻\nForm +2 ions"] --> IONIC
G6["Group 6 non-metals\nGain 2 e⁻\nForm −2 ions"] --> IONIC
G7["Group 7 non-metals\nGain 1 e⁻\nForm −1 ions"] --> IONIC
The position of an element in the periodic table tells you exactly what ion it will form:
| Mistake | Correction |
|---|---|
| Saying atoms "share" electrons in ionic bonding | Ionic bonding involves TRANSFER, not sharing |
| Drawing molecules for ionic compounds | Ionic compounds form giant lattices, not molecules |
| Forgetting to show the charge on each ion | Always write the charge outside the square brackets |
| Getting the charge wrong | Group 1 metals → +1, Group 2 → +2. Group 6 non-metals → −2, Group 7 → −1 |
| Saying "sodium chloride molecule" | Say "formula unit" — there are no molecules in ionic compounds |
| Not showing where the transferred electron ends up | The dot-and-cross diagram must show the transferred electron in the receiving ion |
| Forgetting that ions have the electronic structure of a noble gas | After transfer, both ions should have full outer shells |