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This lesson covers the development of atomic models, the properties of subatomic particles, isotopes, and the concepts of mass number, atomic number, and relative atomic mass. A solid grasp of these fundamentals is essential for everything that follows in A-Level Chemistry.
Our understanding of the atom has evolved over centuries through key experiments and theoretical breakthroughs.
John Dalton proposed that all matter is made of indivisible atoms. He suggested that atoms of the same element are identical and that chemical reactions involve the rearrangement of atoms. While groundbreaking, this model had no concept of internal structure.
J.J. Thomson discovered the electron using cathode ray tubes. He measured the charge-to-mass ratio of electrons and proposed the "plum pudding" model: a sphere of positive charge with negatively charged electrons embedded within it, like plums in a pudding.
Ernest Rutherford directed alpha particles at a thin gold foil. Most passed straight through, but a small fraction were deflected at large angles and some bounced back. This could only be explained if:
Niels Bohr refined the nuclear model by proposing that electrons orbit the nucleus in fixed energy levels (shells). Electrons can move between energy levels by absorbing or emitting specific amounts of energy. This model successfully explained the line spectrum of hydrogen.
The modern model treats electrons as existing in orbitals — regions of space where there is a high probability of finding an electron. Electrons do not follow fixed orbits but are described by wave functions. This model underpins A-Level electron configuration.
Atoms are made of three subatomic particles:
| Particle | Relative mass | Relative charge | Location |
|---|---|---|---|
| Proton | 1 | +1 | Nucleus |
| Neutron | 1 | 0 | Nucleus |
| Electron | 1/1836 (≈ 0.00055) | −1 | Orbitals around nucleus |
The actual masses are:
Key Point: For most A-Level calculations, the mass of the electron is considered negligible compared to protons and neutrons. The relative mass of an electron is approximately 1/1836 that of a proton.
Every element is defined by two key numbers:
The number of neutrons = A − Z.
In a neutral atom, the number of electrons equals the number of protons. When an atom forms an ion, it gains or loses electrons but the number of protons remains unchanged.
An atom is represented as:
ᴬ_Z X
For example, sodium-23: ²³₁₁Na has 11 protons, 12 neutrons (23 − 11), and 11 electrons in the neutral atom.
Exam Tip: If asked for the number of electrons in an ion, remember to adjust: a 2+ ion has lost 2 electrons, a 2− ion has gained 2 electrons.
Isotopes are atoms of the same element (same number of protons / same atomic number) that have different numbers of neutrons (different mass numbers).
| Isotope | Protons | Neutrons | Mass number | Natural abundance (%) |
|---|---|---|---|---|
| ¹H (protium) | 1 | 0 | 1 | 99.98 |
| ²H (deuterium) | 1 | 1 | 2 | 0.02 |
| ¹²C | 6 | 6 | 12 | 98.9 |
| ¹³C | 6 | 7 | 13 | 1.1 |
| ³⁵Cl | 17 | 18 | 35 | 75.8 |
| ³⁷Cl | 17 | 20 | 37 | 24.2 |
Isotopes of the same element have:
Common Misconception: Students sometimes say isotopes have "different chemical properties." This is incorrect. Chemical properties depend on the electron configuration, which is the same for all isotopes of an element.
Because the actual masses of atoms are incredibly small, we use a relative scale based on carbon-12.
Key Definition: Relative atomic mass is a weighted mean because it takes into account the natural abundances of each isotope, not just their masses.
The formula for Aᵣ is:
Aᵣ = Σ (isotopic mass × percentage abundance) / 100
Chlorine has two isotopes: ³⁵Cl (75.8%) and ³⁷Cl (24.2%).
Aᵣ = (35 × 75.8 + 37 × 24.2) / 100
Aᵣ = (2653.0 + 895.4) / 100
Aᵣ = 3548.4 / 100
Aᵣ = 35.5 (to 1 decimal place)
Boron has two isotopes: ¹⁰B (19.9%) and ¹¹B (80.1%).
Aᵣ = (10 × 19.9 + 11 × 80.1) / 100
Aᵣ = (199.0 + 881.1) / 100
Aᵣ = 1080.1 / 100
Aᵣ = 10.8 (to 1 decimal place)
Silicon has three isotopes: ²⁸Si (92.2%), ²⁹Si (4.7%), ³⁰Si (3.1%).
Aᵣ = (28 × 92.2 + 29 × 4.7 + 30 × 3.1) / 100
Aᵣ = (2581.6 + 136.3 + 93.0) / 100
Aᵣ = 2810.9 / 100
Aᵣ = 28.1 (to 1 decimal place)
Exam Tip: Always show your working in relative atomic mass calculations. A common error is to simply average the mass numbers without weighting by abundance. The Aᵣ of chlorine is 35.5, NOT 36 (which would be the simple average of 35 and 37).
When atoms gain or lose electrons, they form ions:
How many protons, neutrons, and electrons are in ⁵⁶₂₆Fe³⁺?
An ion X²⁻ has 10 electrons and 8 protons. Identify the element and write its notation.
| Concept | Key facts |
|---|---|
| Atomic number (Z) | Number of protons; defines the element |
| Mass number (A) | Protons + neutrons |
| Isotopes | Same Z, different A (different neutrons) |
| Relative atomic mass | Weighted mean mass relative to ¹²C / 12 |
| Neutral atom | Protons = electrons |
| Positive ion | Fewer electrons than protons |
| Negative ion | More electrons than protons |
Exam Tip: In multiple-choice questions, you may be asked to identify the correct definition of isotopes. The key phrase is "atoms of the same element with different numbers of neutrons." Do not say "different mass" — be specific about neutrons.